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How can i achieve this in code behind

Last post 03-31-2009, 12:03 AM by cutechat. 4 replies.


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03-27-2009, 12:56 PM 50372

wassimsa
Joined on 12-09-2008
Posts 39

How can i achieve this in code behind

Reply Quote

Hello I would like the following javascript implemented in code behind the reason is I would like the submit to either upload or do something else depoending on some server validation

function submitbutton_click()

{

var submitbutton=document.getElementById('<%=SubmitButton.ClientID %>');

var uploadobj=document.getElementById('<%=Uploader1.ClientID %>');

if(!window.filesuploaded)

{

if(uploadobj.getqueuecount()>0)

{

uploadobj.startupload();

}

else

{

var uploadedcount=parseInt(submitbutton.getAttribute("itemcount"))||0;

if(uploadedcount>0)

{

return true;

}

alert("Please browse files for upload");

}

return false;

}

window.filesuploaded=false;

return true;

}

<.Script>

Thanks

03-27-2009, 11:00 PM 50400 in reply to 50372

cutechat
Joined on 07-22-2004
Posts 2,332

Re: How can i achieve this in code behind

Reply Quote

Hi,

You can use the Micosoft AJAX , and handle the submit click event at server side , and then render script uploadobj.startupload(); to let the uploader start upload.

Regards

Terry

03-28-2009, 6:54 PM 50415 in reply to 50400

wassimsa
Joined on 12-09-2008
Posts 39

Re: How can i achieve this in code behind

Reply Quote

Would it be possible to provide a sample

thanks

03-30-2009, 12:45 PM 50452 in reply to 50415

wassimsa
Joined on 12-09-2008
Posts 39

Re: How can i achieve this in code behind

Reply Quote

I keep getting an error object not supported I took out on the onclientclick event for the submit button and I am trying to upload by calling the following function from code behind. I am using manual upload. When the user clicks on the submit button I would like to be able to know whether I have files in the queue, but I can't find a way to get this info from code behind
Please advice
Thanks

Sub SubmitButton_Click(ByVal sender As Object, ByVal e As EventArgs)
ScriptManager.RegisterStartupScript(Page, Type.GetType("System.String"), "Try Uploading", "StartUpload();", True)
End Sub

function StartUpload()

{

var submitbutton=document.getElementById('<%=SubmitButton.ClientID %>');

var uploadobj=document.getElementById('<%=Uploader1.ClientID %>');

//if(!window.filesuploaded)

//{

if(uploadobj.getqueuecount()>0)

{

uploadobj.startupload();

}

else

{

var uploadedcount=parseInt(submitbutton.getAttribute("itemcount"))||0;

if(uploadedcount>0)

{

return true;

}

alert("Please browse files for upload");

}

// return false;

//}

// window.filesuploaded=false;

// return true;

}

03-31-2009, 12:03 AM 50494 in reply to 50452

cutechat
Joined on 07-22-2004
Posts 2,332

Re: How can i achieve this in code behind

Reply Quote

Hi,

You'd better setTimeout to check whether the uploader is initialized after AJAX postback.

for example:

function StartUpload()
{
var submitbutton=document.getElementById('<%=SubmitButton.ClientID %>');
var uploadobj=document.getElementById('<%=Uploader1.ClientID %>');
if(!uploadobj.startupload)//not initilaized
{
setTimeout(StartUpload,10);
return;
}

...other code.

}

Regards,
Terry