<script type='text/javascript'>

function CuteWebUI_AjaxUploader_OnTaskComplete(task)

{

var div=document.createElement("DIV");

var link=document.createElement("A");

link.setAttribute("href","admin/testUploader/myprefix_"+task.FileName);

link.innerHTML="You have uploaded file : savefiles/myprefix_"+task.FileName;

link.target="_blank";

div.appendChild(link);

document.body.appendChild(div);

}

</script>

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Could you tell me how can I get FileName and put it in : <?php $fileUploaded = task.FileName;  ?>

many thanks in advance

regards

Attourath