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how to deal with duplicate file name

Last post 05-30-2011, 9:03 PM by Kenneth. 4 replies.


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05-28-2011, 3:52 PM 67708

acyk
Joined on 05-29-2011
Posts 4

how to deal with duplicate file name

Reply Quote

Dear sir

I have a question

I just found that image upload to the server with their original name .

what if there are two people upload the image with the same file name ,but in the difference time ?

for example

Jason just upload the image named " iphone.jpg"

few days later , Kevin wants to upload the image also named "iphone.jpg"

can we let all upload file with the unique file name ?

05-29-2011, 9:17 PM 67715 in reply to 67708

Kenneth
Joined on 02-13-2008
Posts 3,886

Re: how to deal with duplicate file name

Reply Quote

Hi acyk,

You can custom the file name by method MoveTo, like below.

In this example, I add the time belore the file name.

<?php require_once "phpuploader/include_phpuploader.php" ?>
<?php session_start(); ?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
   <title>
   example
   </title>
</head>
<body>

           <form id="form1" method="POST">
               <?php
                   $uploader=new PhpUploader();
                   $uploader->MaxSizeKB=10240;
                   $uploader->Name="myuploader";
                   $uploader->InsertText="Select multiple files (Max 10M)";
                   $uploader->AllowedFileExtensions="*.jpg,*.png,*.gif,*.txt,*.zip,*.rar";
                   $uploader->MultipleFilesUpload=true;
                   $uploader->Render();
            ?>
            </form>
<?php
$fileguidlist=@$_POST["myuploader"];
if($fileguidlist)
{
$guidlist=split("/",$fileguidlist);
    foreach($guidlist as $fileguid)
    {

        //get the uploaded file based on GUID
        $mvcfile=$uploader->GetUploadedFile($fileguid);
        if($mvcfile)
        {
        $mvcfile->MoveTo("D:/2005/phpuploader/test/".date("H.i.s").$mvcfile->FileName);
        }
    }

}
?>
   </div>
</body>
</html>

Regards,

ken

05-29-2011, 11:11 PM 67719 in reply to 67715

acyk
Joined on 05-29-2011
Posts 4

Re: how to deal with duplicate file name

Reply Quote

great idea !

thanks for your help

let me try

05-30-2011, 11:38 AM 67728 in reply to 67715

acyk
Joined on 05-29-2011
Posts 4

Re: how to deal with duplicate file name

Reply Quote

<form id="form1" method="POST">
MaxSizeKB=10240;
$uploader->Name="myuploader";
$uploader->InsertText="Select multiple files (Max 10M)";
$uploader->AllowedFileExtensions="*.jpg,*.png,*.gif,*.txt,*.zip,*.rar";
$uploader->MultipleFilesUpload=true;
$uploader->Render();
?>
</form>
GetUploadedFile($fileguid);
if($mvcfile)
{
$mvcfile->MoveTo("/home/ftp/iphone4tw/attach/test/uploads/iPhone4TW-".date("H-i-s")."_".$mvcfile->FileName);
}
}
}
?>
<script type="text/javascript">
function CuteWebUI_AjaxUploader_OnTaskComplete(task)
{
var div=document.createElement("DIV");
div.innerHTML=" [ img]http://attach.iphone4.tw/test/uploads/" + task.FileName + "[/img]<br>";
document.body.appendChild(div);
}
</script>

I have problem to show the final file name here , and file lsit suddenly gone forever

here is my test page , pls advise , thanks

http://attach.iphone4.tw/test/test.php

05-30-2011, 9:03 PM 67739 in reply to 67728

Kenneth
Joined on 02-13-2008
Posts 3,886

Re: how to deal with duplicate file name

Reply Quote

Hi acyk,

Two ways.

1. Remove the <form> tag.

2. Use the example below

<?php require_once "phpuploader/include_phpuploader.php" ?>
<?php session_start(); ?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
   <title>
       Ajax - Multiple files upload
   </title>
   <script type="text/javascript">
       var handlerurl='ajax-multiplefiles-handler.php'
   </script>
   <script type="text/javascript">
   function CuteWebUI_AjaxUploader_OnPostback()
   {
       var uploader = document.getElementById("myuploader");
       var guidlist = uploader.value;

       //Send Request
       var xh;
       if (window.XMLHttpRequest)
           xh = new window.XMLHttpRequest();
       else
           xh = new ActiveXObject("Microsoft.XMLHTTP");

       xh.open("POST", handlerurl, false, null, null);
       xh.setRequestHeader("Content-Type", "application/x-www-form-urlencoded; charset=utf-8");
       xh.send("guidlist=" + guidlist);

       //call uploader to clear the client state
       uploader.reset();

       if (xh.status != 200)
       {
           alert("http error " + xh.status);
           setTimeout(function() { document.write(xh.responseText); }, 10);
           return;
       }

       var filelist = document.getElementById("filelist");
        filelist.style.listStyleType="none";
       var list = eval(xh.responseText); //get JSON objects
       //Process Result:
       for (var i = 0; i < list.length; i++)
       {
           var item = list[i];

           var msg = "

";
           var li = document.createElement("li");
           li.innerHTML = msg;
           filelist.appendChild(li);
       }
   }
   </script>

</head>
<body>
<form id="form1" >
   <div class="demo">
                   <?php
               $uploader=new PhpUploader();
               $uploader->MaxSizeKB=10240;
               $uploader->Name="myuploader";
               $uploader->MultipleFilesUpload=true;
               $uploader->InsertText="Select multiple files (Max 10M)";
               $uploader->AllowedFileExtensions="*.jpg,*.png,*.gif,*.bmp,*.txt,*.zip,*.rar";
               $uploader->Render();
           ?>

           <ol id="filelist">
           </ol>
   </div>
   </form>
</body>
</html>

Regards,

Ken