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How can this be used in a PHP form?

Last post 07-13-2012, 10:28 AM by peterbe. 3 replies.


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07-12-2012, 2:37 PM 74121

peterbe
Joined on 07-12-2012
Posts 3

How can this be used in a PHP form?

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There are no implementation examples for use in a form. For example, how do I make a VAR out of the downloaded filenames to insert into a database?

07-13-2012, 7:10 AM 74122 in reply to 74121

Kenneth
Joined on 02-13-2008
Posts 3,111

Re: How can this be used in a PHP form?

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Hi peterbe,

Please refer to http://phpfileuploader.com/Deployment.html. It shows you how to deploy and use the php uploader in your form.

Step 3 shows you how to get the upload file name, you can write your database code there to save the name into database.

Regards,

Ken

07-13-2012, 10:20 AM 74124 in reply to 74122

peterbe
Joined on 07-12-2012
Posts 3

Re: How can this be used in a PHP form?

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Thanks, Ken. The uploader is not creating the element, $_POST["myuploader"].

It is, however, creating these elements in the $_POST array:

$_POST["UploadLib_Uploader_js"]

and

$_POST["AjaxUploaderFiles "]

Neither of those vars contain a filename. Nor do the other uploader vars in the example. (When echoed, they are empty).

The selected file is moved and saved OK but I am not able to figure out how to write the filename to a var for databasing.

07-13-2012, 10:28 AM 74125 in reply to 74124

peterbe
Joined on 07-12-2012
Posts 3

Re: How can this be used in a PHP form?

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Ooooops. My error. Please disregard all of the above. I initialized "myuploader" as "myUploader". After fixing that discrepancy, everything works fine. Many thanks for your response.